MySQL में जटिल फुटबॉल लीग डायनेमिक ऑर्डरिंग?

आइए इसे चरण दर चरण करते हैं:

घर पर जीते गए गेम और घर पर स्कोर चुनें:

   SELECT COUNT(*) as wins, SUM(G.home_score) as score FROM games G WHERE 
      G.team_id = T.team_id #See 3. query and you'll understand
      G.home_score > away_score

आइए इस परिणाम को HOME_GAMES कहते हैं।

जीते गए गेम और अवे गेम के स्कोर का चयन करें:

SELECT COUNT(*) as wins, SUM(G.away_score) as score FROM games G
WHERE 
  G.team_id = T.team_id #See 3. query and you'll understand
  G.away_score > G.home_score

आइए इस परिणाम को AWAY_GAMES कहते हैं।

जीते गए कुल गेम और कुल स्कोर चुनें:

   SELECT (A.wins + H.wins) AS total_wins, (A.score + H.score) AS total_score FROM
   (AWAY_GAMES) AS A, (HOME_GAMES) AS H, teams T 
   ORDER BY total_wins, total_score

==> AWAY_GAMES और HOME_GAMES को प्रतिस्थापित करके सभी को एक साथ रखें:

SELECT (A.wins + H.wins) AS total_wins, (A.score + H.score) AS total_score FROM 
  (SELECT COUNT(*) as wins, SUM(G.away_score) as score FROM games G
   WHERE 
     G.team_id = T.team_id #See 3. and you'll understand
     G.away_score > G.home_score) AS A, 

   (SELECT COUNT(*) as wins, SUM(G.home_score) as score FROM games G 
   WHERE 
      G.team_id = T.team_id #See 3. and you'll understand
      G.home_score > away_score) AS H, 

   teams T
   ORDER BY total_wins, total_score