Oracle SQL में व्यावसायिक घंटों के आधार पर घंटों की गणना करें

आप सीधे घंटों में अंतर की गणना कर सकते हैं:

SELECT task,
       start_time,
       end_time,
       ROUND(
         (
           -- Calculate the full weeks difference from the start of ISO weeks.
           ( TRUNC( end_time, 'IW' ) - TRUNC( start_time, 'IW' ) ) * (10/24) * (6/7)
           -- Add the full days for the final week.
           + LEAST( TRUNC( end_time ) - TRUNC( end_time, 'IW' ), 6 ) * (10/24)
           -- Subtract the full days from the days of the week before the start date.
           - LEAST( TRUNC( start_time ) - TRUNC( start_time, 'IW' ), 6 ) * (10/24)
           -- Add the hours of the final day
           + LEAST( GREATEST( end_time - TRUNC( end_time ) - 8/24, 0 ), 10/24 )
           -- Subtract the hours of the day before the range starts.
           - LEAST( GREATEST( start_time - TRUNC( start_time ) - 8/24, 0 ), 10/24 )
         )
         -- Multiply to give minutes rather than fractions of full days.
         * 24,
         15 -- Number of decimal places
       ) AS work_day_hours_diff
FROM   your_table;

जो, आपके नमूना डेटा के लिए:

CREATE TABLE your_table ( TASK, START_TIME, END_TIME ) AS
SELECT 'A', DATE '2017-01-16' + INTERVAL '10:00' HOUR TO MINUTE, DATE '2017-01-23' + INTERVAL '11:35' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'B', DATE '2017-01-18' + INTERVAL '17:53' HOUR TO MINUTE, DATE '2017-01-19' + INTERVAL '08:00' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'C', DATE '2017-01-13' + INTERVAL '13:00' HOUR TO MINUTE, DATE '2017-01-17' + INTERVAL '14:52' HOUR TO MINUTE FROM DUAL UNION ALL
SELECT 'D', DATE '2017-01-21' + INTERVAL '10:00' HOUR TO MINUTE, DATE '2017-01-30' + INTERVAL '08:52' HOUR TO MINUTE FROM DUAL;

आउटपुट (दिनांक प्रारूप के साथ YYYY-MM-DD HH24:MI:SS (DY) ):

TASK | START_TIME                | END_TIME                  | WORK_DAY_HOURS_DIFF
:--- | :------------------------ | :------------------------ | ------------------:
A    | 2017-01-16 10:00:00 (MON) | 2017-01-23 11:35:00 (MON) |  61.583333333333333
B    | 2017-01-18 17:53:00 (WED) | 2017-01-19 08:00:00 (THU) |    .116666666666667
C    | 2017-01-13 13:00:00 (FRI) | 2017-01-17 14:52:00 (TUE) |  31.866666666666667
D    | 2017-01-21 10:00:00 (SAT) | 2017-01-30 08:52:00 (MON) |  68.866666666666667

db<>यहां बेला करें

पिछला समाधान:

आप प्रत्येक कार्य दिवस के लिए एक पंक्ति उत्पन्न करने के लिए एक सहसंबद्ध पदानुक्रमित क्वेरी का उपयोग कर सकते हैं और फिर प्रत्येक दिन के घंटों का योग कर सकते हैं:

SELECT task,
       COALESCE( SUM( end_time - start_time ), 0 ) * 24 AS total_hours
FROM   (
  SELECT task,
         GREATEST( t.start_time, d.column_value + INTERVAL '8' HOUR ) AS start_time,
         LEAST( t.end_time, d.column_value + INTERVAL '18' HOUR ) AS end_time
  FROM   your_table t
         LEFT OUTER JOIN
         TABLE(
           CAST(
             MULTISET(
               SELECT TRUNC( t.start_time + LEVEL - 1 )
               FROM   DUAL
               WHERE  TRUNC( t.start_time + LEVEL - 1 ) - TRUNC( t.start_time + LEVEL - 1, 'iw' ) < 6
               CONNECT BY TRUNC( t.start_time + LEVEL - 1 ) < t.end_time
             ) AS SYS.ODCIDATELIST
           )
         ) d
         ON (   t.end_time   > d.column_value + INTERVAL  '8' HOUR
            AND t.start_time < d.column_value + INTERVAL '18' HOUR )
)
GROUP BY task;