/* The type has to be SQL type so that it is also visible for Java. */
create or replace type widgets_t is table of varchar2(32767);
/
create or replace and compile java source named "so19ja" as
import java.lang.*;
public class so19ja {
public static String[] get_widgets_as_array() {
String[] widgets = new String[]{"foo", "bar", "zoo"};
return widgets;
}
public static java.sql.Array array_wrapper(
String typeName,
Object elements
) throws java.sql.SQLException {
oracle.jdbc.OracleDriver ora = new oracle.jdbc.OracleDriver();
java.sql.Connection conn = ora.defaultConnection();
oracle.jdbc.OracleConnection oraConn =
(oracle.jdbc.OracleConnection)conn;
/* Yeah - typeName have to be UPPERCASE, really. */
java.sql.Array arr =
oraConn.createARRAY(typeName.toUpperCase(), elements);
return arr;
}
public static java.sql.Array get_widgets_as_array_wrapped()
throws java.sql.SQLException {
return array_wrapper("widgets_t", get_widgets_as_array());
}
};
/
show errors java source "so19ja"
create or replace function get_widgets_as_array return widgets_t as
language java name 'so19ja.get_widgets_as_array_wrapped() return java.sql.Array';
/
show errors
declare
widgets constant widgets_t := get_widgets_as_array;
begin
for i in widgets.first .. widgets.last loop
dbms_output.put_line('widgets(' || i || ') = ' || widgets(i));
end loop;
end;
/
प्रिंट:
widgets(1) = foo
widgets(2) = bar
widgets(3) = zoo
PL/SQL procedure successfully completed.
यह भी देखें:oracle.sql.ARRAY ऑब्जेक्ट कैसे बनाएं?