MySQL - समय ओवरलैप ढूँढना

संपादित करें:अतिरिक्त जानकारी का उपयोग करते हुए, यह अब केवल उन बुकिंग को दिखाने तक सीमित है जो कुछ पहले की बुकिंग से टकराती हैं।

मुझे लगता है कि यह चाल चलेगा:

SELECT DISTINCT
    b2.booking_id, -- The later booking
    b2.booking_start,
    b2.booking_end,
    b2.creation_date,
    rb1.resource_id, -- The resource over which the two bookings clash
    b1.booking_id, -- The earlier booking
    b1.booking_start,
    b1.booking_end
FROM resource_booked rb1
    INNER JOIN booking b1 ON b1.booking_id = rb1.booking_id
    INNER JOIN booking b2 ON b1.booking_id <> b2.booking_id
        AND b2.booking_start BETWEEN b1.booking_start AND b1.booking_end
    INNER JOIN resource_booked rb2 ON rb2.resource_id = rb1.resource_id
        AND rb2.booking_id = b2.booking_id

इस तरह इसका परीक्षण किया गया:

use tempdb

drop table resource_booked 
drop table Booking

create table Booking
(
    booking_id int,
    booking_start datetime,
    booking_end datetime,
    creation_date datetime
)

create table resource_booked 
(
    booking_id int,
    resource_id int
)

insert Booking values (1, '1 january 2000', '1 march 2000', '1 january 2000')
insert Booking values (2, '1 february 2000', '1 may 2000', '2 january 2000')
insert Booking values (3, '1 april 2000', '1 june 2000', '3 january 2000')
insert Booking values (4, '1 july 2000', '1 august 2000', '4 january 2000')

insert resource_booked values (1, 1)
insert resource_booked values (2, 1)
insert resource_booked values (3, 1)
insert resource_booked values (4, 1)
insert resource_booked values (1, 2)
insert resource_booked values (3, 2)