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Oracle sql में एक तालिका के रूप में सीमांकित स्ट्रिंग का चयन करना

यह समाधान कॉलम (चौड़ाई, ऊंचाई, ...) और मानों की मनमानी संख्या के साथ काम करता है।

-- your test data  
with data(val) as
 (select 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' from dual),

-- split by ,
cols as
 (select regexp_substr(str, '[^,]+', 1, level) val
    from (select val as str from data)
  connect by regexp_substr((select val as str from data),
                           '[^,]+',
                           1,
                           level) is not null),

-- split by :
hdr_and_cols as
 (select substr(val, 1, instr(val, ':') - 1) as hdr,
         substr(val, instr(val, ':') + 1) as val
    from cols),

-- split by |
hdr_lvl_vals as
 (select distinct x.hdr,
                  level as entry,
                  regexp_substr(x.val, '[^|]+', 1, level) as val
    from hdr_and_cols x
  connect by regexp_substr(x.val, '[^|]+', 1, level) is not null)

select * from hdr_lvl_vals;

परिणाम:

hdr     entry   value
---------------------
Height  1       25
Height  2       5
Height  3       6
Height  4       45
Length  1       35
Length  2       6
Length  3       3
Length  4       4
Width   1       10
Width   2       7
Width   3       20
Width   4       45

आप परिणाम को अपनी पसंद के अनुसार प्रारूपित कर सकते हैं उदा.

-- your test data  
with data(val) as
 (select 'Width:10|7|20|45,Height:25|5|6|45,Length:35|6|3|4' from dual),

-- split by ,
cols as
 (select regexp_substr(str, '[^,]+', 1, level) val
    from (select val as str from data)
  connect by regexp_substr((select val as str from data),
                           '[^,]+',
                           1,
                           level) is not null),

-- split by :
hdr_and_cols as
 (select substr(val, 1, instr(val, ':') - 1) as hdr,
         substr(val, instr(val, ':') + 1) as val
    from cols),

-- split by |
hdr_lvl_vals as
 (select distinct x.hdr,
                  level as entry,
                  regexp_substr(x.val, '[^|]+', 1, level) as val
    from hdr_and_cols x
  connect by regexp_substr(x.val, '[^|]+', 1, level) is not null)

-- format output
select w.val as width, h.val as heigth, l.val as length
  from (select entry, val from hdr_lvl_vals where hdr = 'Width') w,
       (select entry, val from hdr_lvl_vals where hdr = 'Height') h,
       (select entry, val from hdr_lvl_vals where hdr = 'Length') l,
       (select level as entry
          from dual
        connect by level <= (select max(entry) from hdr_lvl_vals)) r
 where r.entry = w.entry
   and r.entry = h.entry
   and r.entry = l.entry;

आउटपुट:

WIDTH   HEIGTH  LENGTH
--------------------
10      25      35
7       5       6
20      6       3
45      45      4


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