यहाँ एक तरकीब है जिसका उपयोग आप कर सकते हैं यदि संदेश एक सरणी होने की गारंटी है:
> db.messages.find()
{ "Category" : 1, "Messages" : [ "Msg1", "Msg2" ], "Value" : 1 }
{ "Category" : 1, "Messages" : [ ], "Value" : 10 }
{ "Category" : 1, "Messages" : [ "Msg1", "Msg3" ], "Value" : 100 }
{ "Category" : 2, "Messages" : [ "Msg4" ], "Value" : 1000 }
{ "Category" : 2, "Messages" : [ "Msg5" ], "Value" : 10000 }
{ "Category" : 3, "Messages" : [ ], "Value" : 100000 }
> var group1 = {
"$group": {
"_id": "$Category",
"Value": {
"$sum": "$Value"
},
"Messages": {
"$push": "$Messages"
}
}
};
> var project1 = {
"$project": {
"Value": 1,
"Messages": {
"$cond": [
{
"$eq": [
"$Messages",
[ [ ] ]
]
},
[ [ null ] ],
"$Messages"
]
}
}
};
> db.messages.aggregate( group1, project1 )
{ "_id" : 3, "Value" : 100000, "Messages" : [ [ null ] ] }
{ "_id" : 2, "Value" : 11000, "Messages" : [ [ "Msg4" ], [ "Msg5" ] ] }
{ "_id" : 1, "Value" : 111, "Messages" : [ [ "Msg1", "Msg2" ], [ ], [ "Msg1", "Msg3" ] ] }
अब दो बार आराम करें और एकल संदेश सरणी प्राप्त करने के लिए पुन:समूहित करें।
> var unwind = {"$unwind":"$Messages"};
> var group2 = {
$group: {
"_id": "$_id",
"Value": {
"$first": "$Value"
},
"Messages": {
"$addToSet": "$Messages"
}
}
};
> var project2 = {
"$project": {
"Category": "$_id",
"_id": 0,
"Value": 1,
"Messages": {
"$cond": [
{
"$eq": [
"$Messages",
[ null ]
]
},
[ ],
"$Messages"
]
}
}
};
> db.messages.aggregate(group1, project1, unwind, unwind, group2 ,project2 )
{ "Value" : 111, "Messages" : [ "Msg3", "Msg2", "Msg1" ], "Category" : 1 }
{ "Value" : 11000, "Messages" : [ "Msg5", "Msg4" ], "Category" : 2 }
{ "Value" : 100000, "Messages" : [ ], "Category" : 3 }