कॉलम में पंक्ति डेटा के एसक्यूएल को जोड़ना

DECLARE @t TABLE (
    TransNo VARCHAR(20),
    Serial INT,
    Project INT
)

INSERT INTO @t (TransNo, Serial, Project)
VALUES
    ('A00000000000001', 1, 100),
    ('A00000000000001', 2, 200),
    ('A00000000000001', 3, 201),
    ('A00000000000001', 4, 101),
    ('A00000000000002', 1, 100),
    ('A00000000000002', 2, 101),
    ('A00000000000003', 1, 100),
    ('A00000000000003', 2, 200),
    ('A00000000000004', 1, 200),
    ('A00000000000004', 2, 100),
    ('A00000000000005', 1, 101),
    ('A00000000000005', 2, 100)

SELECT *, CProject = (
    SELECT DISTINCT [text()] = t2.Project
    FROM @t t2
    WHERE t2.TransNo = t1.TransNo
    ORDER BY t2.Project
    FOR XML PATH('')
)
FROM @t t1

आउटपुट -

TransNo              Serial      Project     CProject
-------------------- ----------- ----------- --------------
A00000000000001      1           100         100101200201
A00000000000001      2           200         100101200201
A00000000000001      3           201         100101200201
A00000000000001      4           101         100101200201
A00000000000002      1           100         100101
A00000000000002      2           101         100101
A00000000000003      1           100         100200
A00000000000003      2           200         100200
A00000000000004      1           200         100200
A00000000000004      2           100         100200
A00000000000005      1           101         100101
A00000000000005      2           100         100101

[text()] के साथ -

100101200201

बिना [text()] . के -

<Project>100</Project><Project>101</Project><Project>200</Project><Project>201</Project>

अधिक विवरण - http:// www.codeproject.com/Articles/691102/String-Aggregation-in-the-World-of-SQL-Server

अपडेट -

SELECT *, CProject = (
    SELECT [text()] = t2.Project
    FROM (
        SELECT t2.Project, Serial = MIN(t2.Serial)
        FROM @t t2
        WHERE t2.TransNo = t1.TransNo
        GROUP BY t2.Project
    ) t2
    ORDER BY t2.Serial
    FOR XML PATH('')
)
FROM @t t1