SELECT [Month] = DATENAME(MONTH, M), Sponsor, Client, c,
[dates] = STUFF((SELECT ', ' + RTRIM(DATEPART(DAY, [date]))
FROM dbo.booking AS b
WHERE b.Sponsor = x.Sponsor
AND b.Client = x.Client
AND b.[date] >= x.M AND b.[date] < DATEADD(MONTH, 1, x.M)
ORDER BY [date]
FOR XML PATH('')), 1, 2, '')
FROM
(
SELECT
M = DATEADD(MONTH, DATEDIFF(MONTH, '19000101', [date]), '19000101'),
Sponsor,
Client,
COUNT(booking_id) AS c
FROM dbo.booking
GROUP BY DATEADD(MONTH, DATEDIFF(MONTH, '19000101', [date]), '19000101'),
Sponsor,
Client
) AS x
ORDER BY M, Sponsor, Client;
ध्यान दें कि यदि प्रायोजक/ग्राहक के संयोजन की एक ही दिन में दो बुकिंग हैं, तो सूची में दिन की संख्या दो बार दिखाई देगी।
संपादित करें यहां बताया गया है कि मैंने कैसे परीक्षण किया:
DECLARE @booking TABLE
(
booking_id INT IDENTITY(1,1) PRIMARY KEY,
[date] DATE,
Sponsor VARCHAR(32),
Client VARCHAR(32)
);
INSERT @booking([date], Sponsor, Client) VALUES
('20120312','AB','y'), ('20120315','AB','y'), ('20120318','AB','y'),
('20120316','FE','x'), ('20120319','FE','x'), ('20120321','FE','x'), ('20120320','FE','x'),
('20120404','AB','x'), ('20120408','AB','x');
SELECT [Month] = DATENAME(MONTH, M), Sponsor, Client, c,
[dates] = STUFF((SELECT ', ' + RTRIM(DATEPART(DAY, [date]))
FROM @booking AS b
WHERE b.Sponsor = x.Sponsor
AND b.Client = x.Client
AND b.[date] >= x.M AND b.[date] < DATEADD(MONTH, 1, x.M)
ORDER BY [date]
FOR XML PATH('')), 1, 2, '')
FROM
(
SELECT
M = DATEADD(MONTH, DATEDIFF(MONTH, '19000101', [date]), '19000101'),
Sponsor,
Client,
COUNT(booking_id) AS c
FROM @booking
GROUP BY DATEADD(MONTH, DATEDIFF(MONTH, '19000101', [date]), '19000101'),
Sponsor,
Client
) AS x
ORDER BY M, Sponsor, Client;
परिणाम:
Month Sponsor Client c dates
------- ------- ------- ------- --------------
March AB y 3 12, 15, 18
March FE x 4 16, 19, 20, 21
April AB x 2 4, 8