डुप्लिकेट अंग्रेजी नामों का पता लगाएं

अनुक्रमण करते समय मैं पहले नाम पर एक समानार्थी फ़िल्टर का उपयोग करूंगा, ताकि आपके पास सभी संभावित संयोजन हों (बॉब -> रॉबर्ट, रॉबर्ट -> बॉब, आदि ...)। आपके पास मौजूद मौजूदा उपयोगकर्ताओं को अनुक्रमित करें।

फिर कुछ अस्पष्ट प्रश्न पूछने के लिए QueryParser (विश्लेषक में SynonymFilter के बिना) का उपयोग करें।

यह वह कोड है जिसके साथ मैं आया था:

public class NameDuplicateTests {
    private Analyzer analyzer;
    private IndexSearcher searcher;
    private IndexReader reader;
    private QueryParser qp;

    private final static Multimap<String, String> firstNameSynonyms;
    static {
        firstNameSynonyms = HashMultimap.create();
        List<String> robertSynonyms = ImmutableList.of("Bob", "Bobby", "Robert");
        for (String name: robertSynonyms) {
            firstNameSynonyms.putAll(name, robertSynonyms);
        }
        List<String> willSynonyms = ImmutableList.of("William", "Will", "Bill", "Billy");
        for (String name: willSynonyms) {
            firstNameSynonyms.putAll(name, willSynonyms);
        }
    }

    public static Analyzer createAnalyzer() {
        return new Analyzer() {
            @Override
            public TokenStream tokenStream(String fieldName, Reader reader) {
                TokenStream tokenizer = new WhitespaceTokenizer(reader);
                if (fieldName.equals("firstName")) {
                    tokenizer = new SynonymFilter(tokenizer, new SynonymEngine() {
                        @Override
                        public String[] getSynonyms(String s) throws IOException {
                            return firstNameSynonyms.get(s).toArray(new String[0]);
                        }
                    });
                }
                return tokenizer;
            }
        };
    }


    @Before
    public void setUp() throws Exception {
        Directory dir = new RAMDirectory();
        analyzer = createAnalyzer();

        IndexWriter writer = new IndexWriter(dir, analyzer, IndexWriter.MaxFieldLength.UNLIMITED);
        ImmutableList<String> firstNames = ImmutableList.of("William", "Robert", "Bobby", "Will", "Anton");
        ImmutableList<String> lastNames = ImmutableList.of("Robert", "Williams", "Mayor", "Bob", "FunkyMother");

        for (int id = 0; id < firstNames.size(); id++) {
            Document doc = new Document();
            doc.add(new Field("id", String.valueOf(id), Field.Store.YES, Field.Index.NOT_ANALYZED));
            doc.add(new Field("firstName", firstNames.get(id), Field.Store.YES, Field.Index.ANALYZED));
            doc.add(new Field("lastName", lastNames.get(id), Field.Store.YES, Field.Index.NOT_ANALYZED));
            writer.addDocument(doc);
        }
        writer.close();

        qp = new QueryParser(Version.LUCENE_30, "firstName", new WhitespaceAnalyzer());
        searcher = new IndexSearcher(dir);
        reader = searcher.getIndexReader();
    }

    @After
    public void tearDown() throws Exception {
        searcher.close();
    }

    @Test
    public void testNameFilter() throws Exception {
        search("+firstName:Bob +lastName:Williams");
        search("+firstName:Bob +lastName:Wolliam~");
    }

    private void search(String query) throws ParseException, IOException {
        Query q = qp.parse(query);
        System.out.println(q);
        TopDocs res = searcher.search(q, 3);
        for (ScoreDoc sd: res.scoreDocs) {
            Document doc = reader.document(sd.doc);
            System.out.println("Found " + doc.get("firstName") + " " + doc.get("lastName"));
        }
    }
}

जिसके परिणाम:

+firstName:Bob +lastName:Williams
Found Robert Williams
+firstName:Bob +lastName:wolliam~0.5
Found Robert Williams

आशा है कि इससे मदद मिलेगी!