निम्नलिखित पर विचार करें:
स्कीमा
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(user_id INT NOT NULL
,status CHAR(3) NOT NULL
,date DATE NOT NULL
,PRIMARY KEY(user_id,date)
);
INSERT INTO my_table VALUES
(1, 'GRE', '2018-09-02'),
(1, 'GRE', '2018-09-03'),
(1, 'PRO', '2018-09-04'),
(1, 'PRO', '2018-09-05'),
(1, 'PRO', '2018-09-06'),
(1, 'GRE', '2018-09-07'),
(1, 'GRE', '2018-09-08'),
(1, 'GRE', '2018-09-09'),
(1, 'GRE', '2018-09-10'),
(2, 'GRE', '2018-09-02'),
(2, 'GRE', '2018-09-03'),
(2, 'PRO', '2018-09-04'),
(2, 'PRO', '2018-09-05'),
(2, 'PRO', '2018-09-06'),
(2, 'GRE', '2018-09-07'),
(2, 'GRE', '2018-09-08'),
(2, 'GRE', '2018-09-09'),
(2, 'GRE', '2018-09-10');
प्रश्न
WITH t AS (
SELECT user_id
, status
, date
, DENSE_RANK() OVER (PARTITION BY user_id ORDER BY date)
- DENSE_RANK() OVER (PARTITION BY user_id,status ORDER BY DATE) grp
FROM my_table
)
SELECT t.user_id
, t.status
, MIN(t.date) start
, MAX(t.date) finish
FROM t
GROUP
BY user_id
, status
, grp
ORDER
BY user_id
, start;
+---------+--------+------------+------------+
| user_id | status | start | finish |
+---------+--------+------------+------------+
| 1 | GRE | 2018-09-02 | 2018-09-03 |
| 1 | PRO | 2018-09-04 | 2018-09-06 |
| 1 | GRE | 2018-09-07 | 2018-09-10 |
| 2 | GRE | 2018-09-02 | 2018-09-03 |
| 2 | PRO | 2018-09-04 | 2018-09-06 |
| 2 | GRE | 2018-09-07 | 2018-09-10 |
+---------+--------+------------+------------+